What is the general solution for 5sec(θ)=4sec(θ)+sqrt(2) ?

The general solution for 5sec(θ)=4sec(θ)+sqrt(2) is θ= pi/4+2pin,θ=(7pi)/4+2pin

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5sec(θ)=4sec(θ)+sqrt(2)

5 sec (θ) = 4 sec (θ) + 2

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

5 sec (θ) = 4 sec (θ) + 2

Solve by substitution

sec (θ) = 2

sec (θ) = 2 : θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Combine all the solutions

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

4 sec (π x) + 6 = - 2

x, y - 1 = - 4 + 3 sin (4 x - \frac{π}{4})

64 = 81 + 25 - 90 (cos (C))

sin^{2} (a - \frac{π}{8}) = \frac{2}{3}

cos^{4} (x) - 3 cos^{2} (x) = 4

What is the general solution for 5sec(θ)=4sec(θ)+sqrt(2) ?
The general solution for 5sec(θ)=4sec(θ)+sqrt(2) is θ= pi/4+2pin,θ=(7pi)/4+2pin