What is the general solution for 10cos(θ)=-5cos(θ) ?

The general solution for 10cos(θ)=-5cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10cos(θ)=-5cos(θ)

10 cos (θ) = - 5 cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

10 cos (θ) = - 5 cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

tan (2 θ) = 1.33

2 cos (2 t) + 2 cos^{2} (t) = 0

5 \cdot cos (x) + 4 - 2 \cdot sin (x) = 0

sin (x) = - 0.54

tan (2 θ) = 1.82

What is the general solution for 10cos(θ)=-5cos(θ) ?
The general solution for 10cos(θ)=-5cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin