What is the general solution for sin(x)=-0.12 ?

The general solution for sin(x)=-0.12 is x=-0.12028…+2pin,x=pi+0.12028…+2pin

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sin(x)=-0.12

sin (x) = - 0.12

x = - 0.12028 \dots + 2 πn, x = π + 0.12028 \dots + 2 πn

Degrees

x = - 6.89210 \dots^{\circ} + 36 0^{\circ} n, x = 186.89210 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = - 0.12

Apply trig inverse properties

sin (x) = - 0.12

General solutions for

sin (x) = - 0.12

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- 0.12) + 2 πn, x = π + arcsin (0.12) + 2 πn

x = arcsin (- 0.12) + 2 πn, x = π + arcsin (0.12) + 2 πn

Show solutions in decimal form

x = - 0.12028 \dots + 2 πn, x = π + 0.12028 \dots + 2 πn

tan (θ) = \frac{3}{4}, 0 \leq θ < \frac{π}{2}

cot (a) = \frac{5}{7}

2 cos^{2} (x - 1) = 0

\frac{1}{cot ^{2} ( x )} + \frac{3}{cot ( x )} = 0

b, \frac{sin ( 6 5 ^{\circ} )}{14} = \frac{sin ( b )}{9}

What is the general solution for sin(x)=-0.12 ?
The general solution for sin(x)=-0.12 is x=-0.12028…+2pin,x=pi+0.12028…+2pin