What is the general solution for 0=2sin(x+1)+1 ?

The general solution for 0=2sin(x+1)+1 is x=(7pi)/6+2pin-1,x=(11pi)/6+2pin-1

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0=2sin(x+1)+1

0 = 2 sin (x + 1) + 1

x = \frac{7 π}{6} + 2 πn - 1, x = \frac{11 π}{6} + 2 πn - 1

Solution steps

0 = 2 sin (x + 1) + 1

Switch sides

2 sin (x + 1) + 1 = 0

Move

1

to the right side

2 sin (x + 1) = - 1

Divide both sides by

2

sin (x + 1) = - \frac{1}{2}

General solutions for

sin (x + 1) = - \frac{1}{2}

x + 1 = \frac{7 π}{6} + 2 πn, x + 1 = \frac{11 π}{6} + 2 πn

Solve

x + 1 = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{6} + 2 πn - 1

Solve

x + 1 = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{6} + 2 πn - 1

x = \frac{7 π}{6} + 2 πn - 1, x = \frac{11 π}{6} + 2 πn - 1

tan (θ) \cdot 10 = 10

4 cos (x) + tan (4 5^{\circ}) = 0.6

sin (5 x + 8) = cos (9 x - 16)

cos (x^{\circ}) = \frac{125}{174}

csc (θ) = 23

What is the general solution for 0=2sin(x+1)+1 ?
The general solution for 0=2sin(x+1)+1 is x=(7pi)/6+2pin-1,x=(11pi)/6+2pin-1