What is the general solution for solvefor θ,tan(2θ)=-1 ?

The general solution for solvefor θ,tan(2θ)=-1 is θ=(3pi)/8+(pin)/2

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solvefor θ,tan(2θ)=-1

solve for

θ, tan (2 θ) = - 1

θ = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

tan (2 θ) = - 1

General solutions for

tan (2 θ) = - 1

2 θ = \frac{3 π}{4} + πn

Solve

2 θ = \frac{3 π}{4} + πn : θ = \frac{3 π}{8} + \frac{πn}{2}

θ = \frac{3 π}{8} + \frac{πn}{2}

3 cos (z + 1.2) = 2

\frac{1}{2} = \frac{3}{2} \cdot cos (x)

cos (\frac{x}{2}) = - 12

4 sin (β) + 2 = 3 + 2 sin (β)

3 sin^{2} (x) = cos (x)

What is the general solution for solvefor θ,tan(2θ)=-1 ?
The general solution for solvefor θ,tan(2θ)=-1 is θ=(3pi)/8+(pin)/2