What is the general solution for 3tan^2(x)=19 ?

The general solution for 3tan^2(x)=19 is x=1.19256…+pin,x=-1.19256…+pin

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3tan^2(x)=19

3 tan^{2} (x) = 19

x = 1.19256 \dots + πn, x = - 1.19256 \dots + πn

Solution steps

3 tan^{2} (x) = 19

Solve by substitution

tan (x) = \frac{19}{3}, tan (x) = - \frac{19}{3}

tan (x) = \frac{19}{3} : x = arctan (\frac{19}{3}) + πn

tan (x) = - \frac{19}{3} : x = arctan (- \frac{19}{3}) + πn

Combine all the solutions

x = arctan (\frac{19}{3}) + πn, x = arctan (- \frac{19}{3}) + πn

Show solutions in decimal form

x = 1.19256 \dots + πn, x = - 1.19256 \dots + πn

3.6 = 0.116 cos (4.17 x)

cos (x) = \frac{3}{2}, sin (2 x), - 9 0^{\circ} \leq x \leq 0^{\circ}

sin (x) = 2 \cdot 589.594 \cdot 1 0^{- 9} \cdot 300 \cdot 1 0^{3}

sec (x) = - \frac{\frac{1}{2}}{3}

cos^{2} (θ) + \frac{2 0 ^{2} cos ( θ )}{9.81 ( 1 )} - 1 = 0

What is the general solution for 3tan^2(x)=19 ?
The general solution for 3tan^2(x)=19 is x=1.19256…+pin,x=-1.19256…+pin