What is the general solution for solvefor θ,y=sin(θ) ?

The general solution for solvefor θ,y=sin(θ) is θ=arcsin(y)+2pin,θ=pi+arcsin(-y)+2pin

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solvefor θ,y=sin(θ)

solve for

θ, y = sin (θ)

θ = arcsin (y) + 2 πn, θ = π + arcsin (- y) + 2 πn

Solution steps

y = sin (θ)

Switch sides

sin (θ) = y

Apply trig inverse properties

θ = arcsin (y) + 2 πn, θ = π + arcsin (- y) + 2 πn

sec^{2} (x) - 4 tan^{2} (x) = 0

6 cos^{2} (x) + cos (2 x) = 5

tanh (m L) = 0.99

tan (θ) = 4.8844

5 cos (x) = 5 - 5 cos (x)

What is the general solution for solvefor θ,y=sin(θ) ?
The general solution for solvefor θ,y=sin(θ) is θ=arcsin(y)+2pin,θ=pi+arcsin(-y)+2pin