What is the general solution for sin(2x+20)-1=(-1)/2 ?

The general solution for sin(2x+20)-1=(-1)/2 is x=-10+pin+pi/(12),x=-10+pin+(5pi)/(12)

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sin(2x+20)-1=(-1)/2

sin (2 x + 20) - 1 = \frac{- 1}{2}

x = - 10 + πn + \frac{π}{12}, x = - 10 + πn + \frac{5 π}{12}

Solution steps

sin (2 x + 20) - 1 = \frac{- 1}{2}

Move

1

to the right side

sin (2 x + 20) = \frac{1}{2}

General solutions for

sin (2 x + 20) = \frac{1}{2}

2 x + 20 = \frac{π}{6} + 2 πn, 2 x + 20 = \frac{5 π}{6} + 2 πn

Solve

2 x + 20 = \frac{π}{6} + 2 πn : x = - 10 + πn + \frac{π}{12}

Solve

2 x + 20 = \frac{5 π}{6} + 2 πn : x = - 10 + πn + \frac{5 π}{12}

x = - 10 + πn + \frac{π}{12}, x = - 10 + πn + \frac{5 π}{12}

x, sin (x + \frac{π}{2}) - cos^{2} (x) = 0

0 = 4 + 3 cos (θ)

cos (θ) = \frac{6}{8}

x, 4 cos (x) \cdot sin (y) = 1

arctan (\frac{1}{4} x) - π - arctan (\frac{x}{100}) = - π

What is the general solution for sin(2x+20)-1=(-1)/2 ?
The general solution for sin(2x+20)-1=(-1)/2 is x=-10+pin+pi/(12),x=-10+pin+(5pi)/(12)