What is the general solution for cos^2(x)+2=sin(x) ?

The general solution for cos^2(x)+2=sin(x) is No Solution for x\in\mathbb{R}

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cos^2(x)+2=sin(x)

cos^{2} (x) + 2 = sin (x)

No Solution for x \in R

Solution steps

cos^{2} (x) + 2 = sin (x)

Subtract

sin (x)

from both sides

cos^{2} (x) + 2 - sin (x) = 0

Rewrite using trig identities

3 - sin (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = - \frac{1 + 13}{2}, sin (x) = \frac{13 - 1}{2}

sin (x) = - \frac{1 + 13}{2} :

No Solution

sin (x) = \frac{13 - 1}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

- sin (2 x) - 3 cos (x) = 0

x, y = 3 cos (f xx + \frac{π}{2}) + 5

sin (x) cos (x) = sin (x), 0 < x \leq 2 π

cos^{5} (x) - sin (x) = 0

x, y = \frac{1}{5 sin ( 2 x )}

What is the general solution for cos^2(x)+2=sin(x) ?
The general solution for cos^2(x)+2=sin(x) is No Solution for x\in\mathbb{R}