What is the general solution for -arctan(t)=(4-pi)/4 ?

The general solution for -arctan(t)=(4-pi)/4 is t=-tan((4-pi)/4)

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-arctan(t)=(4-pi)/4

- arctan (t) = \frac{4 - π}{4}

t = - tan (\frac{4 - π}{4})

Solution steps

- arctan (t) = \frac{4 - π}{4}

Divide both sides by

- 1

arctan (t) = - \frac{4 - π}{4}

Apply trig inverse properties

t = - tan (\frac{4 - π}{4})

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

cos (5 7^{\circ}) = sin (x)

3 cos (x) = 2 - cos (x)

2 cos^{2} (3 x) - 3 cos (3 x) = - 1, 0 \leq x \leq 2 π

x, z = y^{s i n (x)}

What is the general solution for -arctan(t)=(4-pi)/4 ?
The general solution for -arctan(t)=(4-pi)/4 is t=-tan((4-pi)/4)