What is the general solution for tan^2(θ)+2tan(θ)=0,tan(2θ)+2tan(θ)=0 ?

The general solution for tan^2(θ)+2tan(θ)=0,tan(2θ)+2tan(θ)=0 is No Solution for θ\in\mathbb{R}

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tan^2(θ)+2tan(θ)=0,tan(2θ)+2tan(θ)=0

tan^{2} (θ) + 2 tan (θ) = 0, tan (2 θ) + 2 tan (θ) = 0

No Solution for θ \in R

Solution steps

tan^{2} (θ) + 2 tan (θ) = 0, tan (2 θ) + 2 tan (θ) = 0

Solve by substitution

tan (θ) = 0, tan (θ) = - 2

tan (θ) = 0, tan (2 θ) + 2 tan (θ) = 0 :

No Solution

tan (θ) = - 2, tan (2 θ) + 2 tan (θ) = 0 :

No Solution

Combine all the solutions

No Solution for θ \in R

2 cot (x) csc (x) - csc^{2} (x) = 0

8 tan (a) + 3 = 2 tan (a) + 3

tan (\frac{θ}{2}) = \frac{3}{3}

x, cos (x) + 1 = 0

- 8 sin (x) = 0

What is the general solution for tan^2(θ)+2tan(θ)=0,tan(2θ)+2tan(θ)=0 ?
The general solution for tan^2(θ)+2tan(θ)=0,tan(2θ)+2tan(θ)=0 is No Solution for θ\in\mathbb{R}