What is the general solution for 4sin(2x+pi/6)=2 ?

The general solution for 4sin(2x+pi/6)=2 is x=pin,x=pin+pi/3

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4sin(2x+pi/6)=2

4 sin (2 x + \frac{π}{6}) = 2

x = πn, x = πn + \frac{π}{3}

Solution steps

4 sin (2 x + \frac{π}{6}) = 2

Divide both sides by

4

sin (2 x + \frac{π}{6}) = \frac{1}{2}

General solutions for

sin (2 x + \frac{π}{6}) = \frac{1}{2}

2 x + \frac{π}{6} = \frac{π}{6} + 2 πn, 2 x + \frac{π}{6} = \frac{5 π}{6} + 2 πn

Solve

2 x + \frac{π}{6} = \frac{π}{6} + 2 πn : x = πn

Solve

2 x + \frac{π}{6} = \frac{5 π}{6} + 2 πn : x = πn + \frac{π}{3}

x = πn, x = πn + \frac{π}{3}

8 cos (θ) = 3 - 4 cos (θ)

cos (θ) = \frac{3}{2}, sin (θ)

sin (θ) = 0.788

arctan (θ) = - 3

cos (θ) = \frac{2}{6}

What is the general solution for 4sin(2x+pi/6)=2 ?
The general solution for 4sin(2x+pi/6)=2 is x=pin,x=pin+pi/3