What is the general solution for -5=-5+4sin(-2x+(3pi)/4) ?

The general solution for -5=-5+4sin(-2x+(3pi)/4) is x=-pin+(3pi)/8 ,x=-pin-pi/2+(3pi)/8

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-5=-5+4sin(-2x+(3pi)/4)

- 5 = - 5 + 4 sin (- 2 x + \frac{3 π}{4})

x = - πn + \frac{3 π}{8}, x = - πn - \frac{π}{2} + \frac{3 π}{8}

Solution steps

- 5 = - 5 + 4 sin (- 2 x + \frac{3 π}{4})

Switch sides

- 5 + 4 sin (- 2 x + \frac{3 π}{4}) = - 5

Add

5

to both sides

- 5 + 4 sin (- 2 x + \frac{3 π}{4}) + 5 = - 5 + 5

Simplify

4 sin (- 2 x + \frac{3 π}{4}) = 0

Divide both sides by

4

sin (- 2 x + \frac{3 π}{4}) = 0

General solutions for

sin (- 2 x + \frac{3 π}{4}) = 0

- 2 x + \frac{3 π}{4} = 0 + 2 πn, - 2 x + \frac{3 π}{4} = π + 2 πn

Solve

- 2 x + \frac{3 π}{4} = 0 + 2 πn : x = - πn + \frac{3 π}{8}

Solve

- 2 x + \frac{3 π}{4} = π + 2 πn : x = - πn - \frac{π}{2} + \frac{3 π}{8}

x = - πn + \frac{3 π}{8}, x = - πn - \frac{π}{2} + \frac{3 π}{8}

6 sec^{2} (x) + tan (x) - 9 = 0

3 tan^{2} (x) - cos^{2} (x) = sin^{2} (x)

cos (θ) = \frac{2 π}{3}

3 (tan (θ) - 2) = 2 tan (- 7)

4 cos^{2} (x) + 7 cos (x) = 2

What is the general solution for -5=-5+4sin(-2x+(3pi)/4) ?
The general solution for -5=-5+4sin(-2x+(3pi)/4) is x=-pin+(3pi)/8 ,x=-pin-pi/2+(3pi)/8