What is the general solution for (cos(x)-3)(cos(x)+1)=0 ?

The general solution for (cos(x)-3)(cos(x)+1)=0 is x=pi+2pin

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(cos(x)-3)(cos(x)+1)=0

(cos (x) - 3) (cos (x) + 1) = 0

x = π + 2 πn

Solution steps

(cos (x) - 3) (cos (x) + 1) = 0

Solving each part separately

cos (x) - 3 = 0 or cos (x) + 1 = 0

cos (x) - 3 = 0 :

No Solution

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

4 tan^{2} (x) - 16 tan (x) + 7 = 0

1 - cos (x) = 0.5

arctan (100 x) - arctan (x) = 4 5^{\circ}

tan^{2} (x) - 9 = 0

2 = - 4 - 3 csc (θ)

What is the general solution for (cos(x)-3)(cos(x)+1)=0 ?
The general solution for (cos(x)-3)(cos(x)+1)=0 is x=pi+2pin