What is the general solution for -2sin(2x)= pi/(12) ?

The general solution for -2sin(2x)= pi/(12) is x=-(0.13127…)/2+pin,x= pi/2+(0.13127…)/2+pin

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-2sin(2x)= pi/(12)

- 2 sin (2 x) = \frac{π}{12}

x = - \frac{0.13127 \dots}{2} + πn, x = \frac{π}{2} + \frac{0.13127 \dots}{2} + πn

Solution steps

- 2 sin (2 x) = \frac{π}{12}

Divide both sides by

- 2

sin (2 x) = - \frac{π}{24}

Apply trig inverse properties

2 x = arcsin (- \frac{π}{24}) + 2 πn, 2 x = π + arcsin (\frac{π}{24}) + 2 πn

Solve

2 x = arcsin (- \frac{π}{24}) + 2 πn : x = - \frac{arcsin ( \frac{π}{24} )}{2} + πn

Solve

2 x = π + arcsin (\frac{π}{24}) + 2 πn : x = \frac{π}{2} + \frac{arcsin ( \frac{π}{24} )}{2} + πn

x = - \frac{arcsin ( \frac{π}{24} )}{2} + πn, x = \frac{π}{2} + \frac{arcsin ( \frac{π}{24} )}{2} + πn

Show solutions in decimal form

x = - \frac{0.13127 \dots}{2} + πn, x = \frac{π}{2} + \frac{0.13127 \dots}{2} + πn

cos (x) = \frac{sec ( x )}{4}

sin (10 x) = sin (10 (x + 1))

sin^{2} (θ) + 3 sin (θ) = 0

cos (x) = - 0.7962

1.04 cos^{2} (x) + 0.102 cos (x) - 0.935 = 0

What is the general solution for -2sin(2x)= pi/(12) ?
The general solution for -2sin(2x)= pi/(12) is x=-(0.13127…)/2+pin,x= pi/2+(0.13127…)/2+pin