What is the general solution for solvefor x,5=9.4cos(x) ?

The general solution for solvefor x,5=9.4cos(x) is x=1.00993…+2pin,x=2pi-1.00993…+2pin

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Popular >

solvefor x,5=9.4cos(x)

Solution

solve for

x, 5 = 9.4 cos (x)

Solution

x = 1.00993 \dots + 2 πn, x = 2 π - 1.00993 \dots + 2 πn

Degrees

x = 57.86507 \dots^{\circ} + 36 0^{\circ} n, x = 302.13492 \dots^{\circ} + 36 0^{\circ} n

Solution steps

5 = 9.4 cos (x)

Switch sides

9.4 cos (x) = 5

Multiply both sides by

10

9.4 cos (x) = 5

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere is one digit to the right of the decimal point, therefore multiply by

10

9.4 cos (x) \cdot 10 = 5 \cdot 10

Refine

94 cos (x) = 50

94 cos (x) = 50

Divide both sides by

94

94 cos (x) = 50

Divide both sides by

94

\frac{94 cos ( x )}{94} = \frac{50}{94}

Simplify

cos (x) = \frac{25}{47}

cos (x) = \frac{25}{47}

Apply trig inverse properties

cos (x) = \frac{25}{47}

General solutions for

cos (x) = \frac{25}{47}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{25}{47}) + 2 πn, x = 2 π - arccos (\frac{25}{47}) + 2 πn

x = arccos (\frac{25}{47}) + 2 πn, x = 2 π - arccos (\frac{25}{47}) + 2 πn

Show solutions in decimal form

x = 1.00993 \dots + 2 πn, x = 2 π - 1.00993 \dots + 2 πn

Popular Examples

20=2.891sin(0.016d-1.183)+18.512

20 = 2.891 sin (0.016 d - 1.183) + 18.512

2sin(θ)=-1,0<= θ<2pi

2 sin (θ) = - 1, 0 \leq θ < 2 π

cos(16x)=0

cos (16 x) = 0

sin(θ)=-(sqrt(35))/6

sin (θ) = - \frac{35}{6}

0.6=cos(x)

0.6 = cos (x)

Frequently Asked Questions (FAQ)

What is the general solution for solvefor x,5=9.4cos(x) ?
The general solution for solvefor x,5=9.4cos(x) is x=1.00993…+2pin,x=2pi-1.00993…+2pin