What is the general solution for sin(60)=cos(x+10) ?

The general solution for sin(60)=cos(x+10) is x=360n+20,x=360n+320

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sin(60)=cos(x+10)

sin (6 0^{\circ}) = cos (x + 1 0^{\circ})

x = 36 0^{\circ} n + 2 0^{\circ}, x = 36 0^{\circ} n + 32 0^{\circ}

Solution steps

sin (6 0^{\circ}) = cos (x + 1 0^{\circ})

sin (6 0^{\circ}) = \frac{3}{2}

\frac{3}{2} = cos (x + 1 0^{\circ})

Switch sides

cos (x + 1 0^{\circ}) = \frac{3}{2}

General solutions for

cos (x + 1 0^{\circ}) = \frac{3}{2}

x + 1 0^{\circ} = 3 0^{\circ} + 36 0^{\circ} n, x + 1 0^{\circ} = 33 0^{\circ} + 36 0^{\circ} n

Solve

x + 1 0^{\circ} = 3 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 2 0^{\circ}

Solve

x + 1 0^{\circ} = 33 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 32 0^{\circ}

x = 36 0^{\circ} n + 2 0^{\circ}, x = 36 0^{\circ} n + 32 0^{\circ}

sin (2 x) = 682

0 = 5 \cdot sin (2 π \cdot (- 0.25 - x))

cos (a) = \frac{2}{2}

csc (x) = 1.1223

x, z = sin (5 x) cos (5 y)

What is the general solution for sin(60)=cos(x+10) ?
The general solution for sin(60)=cos(x+10) is x=360n+20,x=360n+320