What is the general solution for sin(2x+64)=(sqrt(3))/2 ?

The general solution for sin(2x+64)=(sqrt(3))/2 is x=-32+pin+pi/6 ,x=-32+pin+pi/3

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sin(2x+64)=(sqrt(3))/2

sin (2 x + 64) = \frac{3}{2}

x = - 32 + πn + \frac{π}{6}, x = - 32 + πn + \frac{π}{3}

Solution steps

sin (2 x + 64) = \frac{3}{2}

General solutions for

sin (2 x + 64) = \frac{3}{2}

2 x + 64 = \frac{π}{3} + 2 πn, 2 x + 64 = \frac{2 π}{3} + 2 πn

Solve

2 x + 64 = \frac{π}{3} + 2 πn : x = - 32 + πn + \frac{π}{6}

Solve

2 x + 64 = \frac{2 π}{3} + 2 πn : x = - 32 + πn + \frac{π}{3}

x = - 32 + πn + \frac{π}{6}, x = - 32 + πn + \frac{π}{3}

sin (θ) = 0, 6

sin (x) = sin (\frac{π}{2})

\frac{sin ( x )}{1 - cos ^{2} ( x )} = sec (x)

cos (2 x) - 2 sin (x) = 1, 0^{\circ} < x \leq 36 0^{\circ}

cos (aπ) - 1 = 0

What is the general solution for sin(2x+64)=(sqrt(3))/2 ?
The general solution for sin(2x+64)=(sqrt(3))/2 is x=-32+pin+pi/6 ,x=-32+pin+pi/3