What is the general solution for 4tan^2(x)=-sqrt(3)tan(x)+tan^2(x) ?

The general solution for 4tan^2(x)=-sqrt(3)tan(x)+tan^2(x) is x=(5pi)/6+pin,x=pin

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4tan^2(x)=-sqrt(3)tan(x)+tan^2(x)

4 tan^{2} (x) = - 3 tan (x) + tan^{2} (x)

x = \frac{5 π}{6} + πn, x = πn

Solution steps

4 tan^{2} (x) = - 3 tan (x) + tan^{2} (x)

Solve by substitution

tan (x) = - \frac{3}{3}, tan (x) = 0

tan (x) = - \frac{3}{3} : x = \frac{5 π}{6} + πn

tan (x) = 0 : x = πn

Combine all the solutions

x = \frac{5 π}{6} + πn, x = πn

\frac{1}{2} = \frac{1}{2} \cdot cos (4.2 t + \frac{π}{6})

120 = 8 3^{2} + 7 5^{2} - 2 \cdot 83 \cdot 75 \cdot cos (x)

cos (u) = \frac{7}{25}

sin (x) + cos (x) = 1, 0 \leq x < 2 π

x, cos^{2} (x + y) = sin^{2} (x + y)

What is the general solution for 4tan^2(x)=-sqrt(3)tan(x)+tan^2(x) ?
The general solution for 4tan^2(x)=-sqrt(3)tan(x)+tan^2(x) is x=(5pi)/6+pin,x=pin