What is the general solution for sin(x)=0.24,0<= x<2pi ?

The general solution for sin(x)=0.24,0<= x<2pi is x=0.24236…,x=pi-0.24236…

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sin(x)=0.24,0<= x<2pi

sin (x) = 0.24, 0 \leq x < 2 π

x = 0.24236 \dots, x = π - 0.24236 \dots

Degrees

x = 13.88654 \dots^{\circ}, x = 166.11345 \dots^{\circ}

Solution steps

sin (x) = 0.24, 0 \leq x < 2 π

Apply trig inverse properties

sin (x) = 0.24

General solutions for

sin (x) = 0.24

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (0.24) + 2 πn, x = π - arcsin (0.24) + 2 πn

x = arcsin (0.24) + 2 πn, x = π - arcsin (0.24) + 2 πn

Solutions for the range

0 \leq x < 2 π

x = 0.24236 \dots, x = π - 0.24236 \dots

sec^{2} (θ) cot (θ) = 8

4 + 5 sin (x) = 1

120 = 23 sin (\frac{π}{6} (x)) + 107

4 sin (3 θ) = 2

cos (x) = cos (3 x) + 2 sin (2 x)

What is the general solution for sin(x)=0.24,0<= x<2pi ?
The general solution for sin(x)=0.24,0<= x<2pi is x=0.24236…,x=pi-0.24236…