What is the general solution for cos(x)=sin((7pi)/6),0<= x<= 2pi ?

The general solution for cos(x)=sin((7pi)/6),0<= x<= 2pi is x=(2pi)/3 ,x=(4pi)/3

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cos(x)=sin((7pi)/6),0<= x<= 2pi

cos (x) = sin (\frac{7 π}{6}), 0 \leq x \leq 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

Solution steps

cos (x) = sin (\frac{7 π}{6}), 0 \leq x \leq 2 π

sin (\frac{7 π}{6}) = - \frac{1}{2}

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

cos (2 x) = \frac{( 3 k - 3 )}{8}

1.5 = 2.75 cos (30 (x - 4)) + 3.25

sin (x) = (\frac{5}{12})

sin (x) = \frac{97}{270}

3 cos (3 x) + 1 = 0

What is the general solution for cos(x)=sin((7pi)/6),0<= x<= 2pi ?
The general solution for cos(x)=sin((7pi)/6),0<= x<= 2pi is x=(2pi)/3 ,x=(4pi)/3