What is the general solution for 1.2sin(24)=1.2sin(x) ?

The general solution for 1.2sin(24)=1.2sin(x) is x=0.41887…+360n,x=180-0.41887…+360n

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1.2sin(24)=1.2sin(x)

1.2 sin (2 4^{\circ}) = 1.2 sin (x)

x = 0.41887 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.41887 \dots + 36 0^{\circ} n

Radians

x = 0.41887 \dots + 2 πn, x = π - 0.41887 \dots + 2 πn

Solution steps

1.2 sin (2 4^{\circ}) = 1.2 sin (x)

Switch sides

1.2 sin (x) = 1.2 sin (2 4^{\circ})

Divide both sides by

1.2

1.2 sin (x) = 1.2 sin (2 4^{\circ})

Divide both sides by

1.2

\frac{1.2 sin ( x )}{1.2} = \frac{1.2 sin ( 2 4 ^{\circ} )}{1.2}

Simplify

sin (x) = sin (2 4^{\circ})

sin (x) = sin (2 4^{\circ})

Apply trig inverse properties

sin (x) = sin (2 4^{\circ})

General solutions for

sin (x) = sin (2 4^{\circ})

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (sin (2 4^{\circ})) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (sin (2 4^{\circ})) + 36 0^{\circ} n

x = arcsin (sin (2 4^{\circ})) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (sin (2 4^{\circ})) + 36 0^{\circ} n

Show solutions in decimal form

x = 0.41887 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.41887 \dots + 36 0^{\circ} n

cos (C) = 20.09 - \frac{27.1441}{19.6}

3 sin (x) - cos^{2} (x) = - 3

csc (4 x) = 0

2 sin (2 x) = - cos (2 x)

cos (2 x) + cos (\frac{π}{2} - 2 x) = - 2

What is the general solution for 1.2sin(24)=1.2sin(x) ?
The general solution for 1.2sin(24)=1.2sin(x) is x=0.41887…+360n,x=180-0.41887…+360n