What is the general solution for 6sin^2(x)=0 ?

The general solution for 6sin^2(x)=0 is x=2pin,x=pi+2pin

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6sin^2(x)=0

6 sin^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

6 sin^{2} (x) = 0

Divide both sides by

6

6 sin^{2} (x) = 0

Divide both sides by

6

6 sin^{2} (x) = 0

Divide both sides by

6

\frac{6 sin ^{2} ( x )}{6} = \frac{0}{6}

Simplify

sin^{2} (x) = 0

sin^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

\frac{1 - tanh ( x )}{1 + tanh ( x )} = 2

40 = tan (ln (18 + 1) + C)

tan (a) = - 26

- 5 cos (x) = 2 sin^{2} (x) + 4

5 sin (θ + 0.4636) = 1

What is the general solution for 6sin^2(x)=0 ?
The general solution for 6sin^2(x)=0 is x=2pin,x=pi+2pin