What is the general solution for 2cos(x)+2sin(x)=0 ?

The general solution for 2cos(x)+2sin(x)=0 is x=(3pi)/4+pin

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2cos(x)+2sin(x)=0

2 cos (x) + 2 sin (x) = 0

x = \frac{3 π}{4} + πn

Degrees

x = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

2 cos (x) + 2 sin (x) = 0

Rewrite using trig identities

2 cos (x) + 2 sin (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{2 cos ( x ) + 2 sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

2 + \frac{2 sin ( x )}{cos ( x )} = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

2 + 2 tan (x) = 0

2 + 2 tan (x) = 0

Move

2

to the right side

2 + 2 tan (x) = 0

Subtract

2

from both sides

2 + 2 tan (x) - 2 = 0 - 2

Simplify

2 tan (x) = - 2

2 tan (x) = - 2

Divide both sides by

2

2 tan (x) = - 2

Divide both sides by

2

\frac{2 tan ( x )}{2} = \frac{- 2}{2}

Simplify

tan (x) = - 1

tan (x) = - 1

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

\frac{3}{2} = sin (arcsin (0) + c_{1})

tan^{2} (x) - sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

3 cos (2 x) + cos (x) = 0

sin (2 v) = sin (1 6^{\circ})

tan (2 x) = \frac{130}{- 270 - 120}

What is the general solution for 2cos(x)+2sin(x)=0 ?
The general solution for 2cos(x)+2sin(x)=0 is x=(3pi)/4+pin