What is the general solution for solvefor θ,tan(θ)=(2sqrt(3))/2 ?

The general solution for solvefor θ,tan(θ)=(2sqrt(3))/2 is θ= pi/3+pin

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solvefor θ,tan(θ)=(2sqrt(3))/2

solve for

θ, tan (θ) = \frac{2 3}{2}

θ = \frac{π}{3} + πn

Degrees

θ = 6 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = \frac{2 3}{2}

Divide the numbers:

\frac{2}{2} = 1

tan (θ) = 3

General solutions for

tan (θ) = 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{3} + πn

θ = \frac{π}{3} + πn

\frac{- 3 + 4 cos ^{2} ( θ )}{1 - 2 sin ( θ )} = a + b sin (θ)

2 sin^{2} (x) - 7 sin (x) = - 3, 0 \leq x \leq 2 π

sin^{2} (x) + cos^{2} (x) = cos (2 x)

(218) sin^{2} (x) + (126) sin (x) - 88 = 0

3 sin (3 x) = 0

What is the general solution for solvefor θ,tan(θ)=(2sqrt(3))/2 ?
The general solution for solvefor θ,tan(θ)=(2sqrt(3))/2 is θ= pi/3+pin