What is the general solution for 2sin(5x)=1 ?

The general solution for 2sin(5x)=1 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5

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2sin(5x)=1

Solution

2 sin (5 x) = 1

Solution

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

Degrees

x = 6^{\circ} + 7 2^{\circ} n, x = 3 0^{\circ} + 7 2^{\circ} n

Solution steps

2 sin (5 x) = 1

Divide both sides by

2

2 sin (5 x) = 1

Divide both sides by

2

\frac{2 sin ( 5 x )}{2} = \frac{1}{2}

Simplify

sin (5 x) = \frac{1}{2}

sin (5 x) = \frac{1}{2}

General solutions for

sin (5 x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{5 π}{6} + 2 πn

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{5 π}{6} + 2 πn

Solve

5 x = \frac{π}{6} + 2 πn : x = \frac{π}{30} + \frac{2 πn}{5}

5 x = \frac{π}{6} + 2 πn

Divide both sides by

5

5 x = \frac{π}{6} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{π}{6}}{5} + \frac{2 πn}{5} : \frac{π}{30} + \frac{2 πn}{5}

\frac{\frac{π}{6}}{5} + \frac{2 πn}{5}

\frac{\frac{π}{6}}{5} = \frac{π}{30}

\frac{\frac{π}{6}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 5}

Multiply the numbers:

6 \cdot 5 = 30

= \frac{π}{30}

= \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}

Solve

5 x = \frac{5 π}{6} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{5}

5 x = \frac{5 π}{6} + 2 πn

Divide both sides by

5

5 x = \frac{5 π}{6} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{5 π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{5 π}{6}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{5 π}{6}}{5} + \frac{2 πn}{5} : \frac{π}{6} + \frac{2 πn}{5}

\frac{\frac{5 π}{6}}{5} + \frac{2 πn}{5}

\frac{\frac{5 π}{6}}{5} = \frac{π}{6}

\frac{\frac{5 π}{6}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{6 \cdot 5}

Multiply the numbers:

6 \cdot 5 = 30

= \frac{5 π}{30}

Cancel the common factor:

5

= \frac{π}{6}

= \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

Popular Examples

cos(2x)=-17/81

cos (2 x) = - \frac{17}{81}

sin^2(θ)+cos(2θ)=0

sin^{2} (θ) + cos (2 θ) = 0

csc(θ)=(sqrt(28))/2 ,sin(θ)

csc (θ) = \frac{28}{2}, sin (θ)

(1+csc(γ))/(cot(γ)+cos(γ))=csc(γ)

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

sin(θ)= 2/6

sin (θ) = \frac{2}{6}

Frequently Asked Questions (FAQ)

What is the general solution for 2sin(5x)=1 ?
The general solution for 2sin(5x)=1 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5