What is the general solution for -5=((sin(x))(cos(x))) ?

The general solution for -5=((sin(x))(cos(x))) is No Solution for x\in\mathbb{R}

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-5=((sin(x))(cos(x)))

- 5 = ((sin (x)) (cos (x)))

No Solution for x \in R

Solution steps

- 5 = ((sin (x)) (cos (x)))

Switch sides

sin (x) cos (x) = - 5

Rewrite using trig identities

sin (x) cos (x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= \frac{sin ( 2 x )}{2}

\frac{sin ( 2 x )}{2} = - 5

Multiply both sides by

2

\frac{sin ( 2 x )}{2} = - 5

Multiply both sides by

2

\frac{2 sin ( 2 x )}{2} = 2 (- 5)

Simplify

sin (2 x) = - 10

sin (2 x) = - 10

- 1 \leq sin (x) \leq 1

No Solution for x \in R

\frac{179}{sin ( x + 2 0 ^{\circ} )} = \frac{125}{sin ( 12 5 ^{\circ} )}

sin (x) = \frac{15}{12}

sin (z) = 5

cos (5 x) cos (x) + sin (5 x) sin (x) = 0

sin (θ) = \frac{5 n + 1}{3} - 2 n

What is the general solution for -5=((sin(x))(cos(x))) ?
The general solution for -5=((sin(x))(cos(x))) is No Solution for x\in\mathbb{R}