What is the general solution for arctan(θ)=arctan(92/44) ?

The general solution for arctan(θ)=arctan(92/44) is θ= 23/11

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arctan(θ)=arctan(92/44)

arctan (θ) = arctan (\frac{92}{44})

θ = \frac{23}{11}

Solution steps

arctan (θ) = arctan (\frac{92}{44})

arctan (\frac{92}{44}) = arctan (\frac{23}{11})

arctan (\frac{92}{44})

= arctan (\frac{23}{11})

arctan (θ) = arctan (\frac{23}{11})

Apply trig inverse properties

arctan (θ) = arctan (\frac{23}{11})

arctan (x) = a \Rightarrow x = tan (a)

θ = tan (arctan (\frac{23}{11}))

tan (arctan (\frac{23}{11})) = \frac{23}{11}

tan (arctan (\frac{23}{11}))

Rewrite using trig identities:

tan (arctan (\frac{23}{11})) = \frac{23}{11}

Use the following identity:

tan (arctan (x)) = x

= \frac{23}{11}

= \frac{23}{11}

θ = \frac{23}{11}

θ = \frac{23}{11}

10 cos (x) - 52 = 0

sin (2 x) = sin^{2} (2 x)

- 8 sin (2 θ + 4 5^{\circ}) = - 4, 0 \leq x < 36 0^{\circ}

sin (b) = \frac{10.21 ( sin ( 61.3 6 ^{\circ} ) )}{11.47}

cos (θ) = 0.513

What is the general solution for arctan(θ)=arctan(92/44) ?
The general solution for arctan(θ)=arctan(92/44) is θ= 23/11