What is the general solution for (sin(50))/(10)=(sin(q))/(12) ?

The general solution for (sin(50))/(10)=(sin(q))/(12) is q=1.16617…+360n,q=180-1.16617…+360n

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(sin(50))/(10)=(sin(q))/(12)

\frac{sin ( 5 0 ^{\circ} )}{10} = \frac{sin ( q )}{12}

q = 1.16617 \dots + 36 0^{\circ} n, q = 18 0^{\circ} - 1.16617 \dots + 36 0^{\circ} n

Solution steps

\frac{sin ( 5 0 ^{\circ} )}{10} = \frac{sin ( q )}{12}

Switch sides

\frac{sin ( q )}{12} = \frac{sin ( 5 0 ^{\circ} )}{10}

Multiply both sides by

10

\frac{5 sin ( q )}{6} = sin (5 0^{\circ})

Multiply both sides by

6

5 sin (q) = 6 sin (5 0^{\circ})

Divide both sides by

5

sin (q) = \frac{6 sin ( 5 0 ^{\circ} )}{5}

Apply trig inverse properties

q = arcsin (\frac{6 sin ( 5 0 ^{\circ} )}{5}) + 36 0^{\circ} n, q = 18 0^{\circ} - arcsin (\frac{6 sin ( 5 0 ^{\circ} )}{5}) + 36 0^{\circ} n

Show solutions in decimal form

q = 1.16617 \dots + 36 0^{\circ} n, q = 18 0^{\circ} - 1.16617 \dots + 36 0^{\circ} n

271.63 = \frac{3 3 \cdot 169.7}{π} cos (α)

2 sin (t) cos (t) + sin (t) - 2 cos (t) - 1 = 0

4 cos^{2} (\frac{x}{2}) - 3 = 0

sin (2 θ) + cos (θ) = 0, 0 \leq θ \leq 2 π

sin (1 0^{\circ}) = 2 sin (a) cos (a)

What is the general solution for (sin(50))/(10)=(sin(q))/(12) ?
The general solution for (sin(50))/(10)=(sin(q))/(12) is q=1.16617…+360n,q=180-1.16617…+360n