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受欢迎的三角函数 >

(sin(b))/(13.1)=(sin(112.1))/(24.1)

解答

\frac{sin ( b )}{13.1} = \frac{sin ( 112. 1 ^{\circ} )}{24.1}

解答

b = 0.52779 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52779 \dots + 36 0^{\circ} n

+1

弧度

b = 0.52779 \dots + 2 πn, b = π - 0.52779 \dots + 2 πn

求解步骤

\frac{sin ( b )}{13.1} = \frac{sin ( 112. 1 ^{\circ} )}{24.1}

在两边乘以

13.1

\frac{sin ( b )}{13.1} = \frac{sin ( 112. 1 ^{\circ} )}{24.1}

在两边乘以

13.1

\frac{13.1 sin ( b )}{13.1} = \frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}

化简

sin (b) = \frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}

sin (b) = \frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}

使用反三角函数性质

sin (b) = \frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}

sin (b) = \frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}) + 36 0^{\circ} n

b = arcsin (\frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{13.1 sin ( 112. 1 ^{\circ} )}{24.1}) + 36 0^{\circ} n

以小数形式表示解

b = 0.52779 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52779 \dots + 36 0^{\circ} n

作图

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