What is the general solution for sin(α)=(120sin(60))/(1200) ?

The general solution for sin(α)=(120sin(60))/(1200) is α=0.08671…+360n,α=180-0.08671…+360n

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sin(α)=(120sin(60))/(1200)

sin (α) = \frac{120 sin ( 6 0 ^{\circ} )}{1200}

α = 0.08671 \dots + 36 0^{\circ} n, α = 18 0^{\circ} - 0.08671 \dots + 36 0^{\circ} n

Radians

α = 0.08671 \dots + 2 πn, α = π - 0.08671 \dots + 2 πn

Solution steps

sin (α) = \frac{120 sin ( 6 0 ^{\circ} )}{1200}

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{3}{2}

sin (α) = \frac{120 \cdot \frac{3}{2}}{1200}

Simplify

\frac{120 \cdot \frac{3}{2}}{1200} : \frac{3}{20}

\frac{120 \cdot \frac{3}{2}}{1200}

Multiply

120 \cdot \frac{3}{2} : 603

120 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 120}{2}

Divide the numbers:

\frac{120}{2} = 60

= 603

= \frac{60 3}{1200}

Cancel the common factor:

60

= \frac{3}{20}

Apply trig inverse properties

sin (α) = \frac{3}{20}

General solutions for

sin (α) = \frac{3}{20}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

α = arcsin (\frac{3}{20}) + 36 0^{\circ} n, α = 18 0^{\circ} - arcsin (\frac{3}{20}) + 36 0^{\circ} n

α = arcsin (\frac{3}{20}) + 36 0^{\circ} n, α = 18 0^{\circ} - arcsin (\frac{3}{20}) + 36 0^{\circ} n

Show solutions in decimal form

α = 0.08671 \dots + 36 0^{\circ} n, α = 18 0^{\circ} - 0.08671 \dots + 36 0^{\circ} n

15.8 \cdot sin (30 x - 90) + 5 = 17

2 sin^{(2)} (x) - sin (x) - 1 = 0

cos^{2} (θ) - 1 = sin^{2} (θ)

- 3 cos^{2} (u) sin (u) - 2 sin (2 u) = 0

cot (θ) = - \frac{7}{24}

What is the general solution for sin(α)=(120sin(60))/(1200) ?
The general solution for sin(α)=(120sin(60))/(1200) is α=0.08671…+360n,α=180-0.08671…+360n