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Popular >

solvefor t,y=3sin(2t-pi/4)

Solution

solve for

t, y = 3 sin (2 t - \frac{π}{4})

Solution

t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}, t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

Solution steps

y = 3 sin (2 t - \frac{π}{4})

Switch sides

3 sin (2 t - \frac{π}{4}) = y

Divide both sides by

3

3 sin (2 t - \frac{π}{4}) = y

Divide both sides by

3

\frac{3 sin ( 2 t - \frac{π}{4} )}{3} = \frac{y}{3}

Simplify

sin (2 t - \frac{π}{4}) = \frac{y}{3}

sin (2 t - \frac{π}{4}) = \frac{y}{3}

Apply trig inverse properties

sin (2 t - \frac{π}{4}) = \frac{y}{3}

General solutions for

sin (2 t - \frac{π}{4}) = \frac{y}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

2 t - \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn, 2 t - \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn

2 t - \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn, 2 t - \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn

Solve

2 t - \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn : t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

2 t - \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn

Move

\frac{π}{4}

to the right side

2 t - \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn

Add

\frac{π}{4}

to both sides

2 t - \frac{π}{4} + \frac{π}{4} = arcsin (\frac{y}{3}) + 2 πn + \frac{π}{4}

Simplify

2 t = arcsin (\frac{y}{3}) + 2 πn + \frac{π}{4}

2 t = arcsin (\frac{y}{3}) + 2 πn + \frac{π}{4}

Divide both sides by

2

2 t = arcsin (\frac{y}{3}) + 2 πn + \frac{π}{4}

Divide both sides by

2

\frac{2 t}{2} = \frac{arcsin ( \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

Simplify

\frac{2 t}{2} = \frac{arcsin ( \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{arcsin ( \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2} : \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

\frac{arcsin ( \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{4}}{2} = \frac{π}{8}

\frac{\frac{π}{4}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{π}{8}

= \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}

Solve

2 t - \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn : t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

2 t - \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn

Move

\frac{π}{4}

to the right side

2 t - \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn

Add

\frac{π}{4}

to both sides

2 t - \frac{π}{4} + \frac{π}{4} = π + arcsin (- \frac{y}{3}) + 2 πn + \frac{π}{4}

Simplify

2 t = π + arcsin (- \frac{y}{3}) + 2 πn + \frac{π}{4}

2 t = π + arcsin (- \frac{y}{3}) + 2 πn + \frac{π}{4}

Divide both sides by

2

2 t = π + arcsin (- \frac{y}{3}) + 2 πn + \frac{π}{4}

Divide both sides by

2

\frac{2 t}{2} = \frac{π}{2} + \frac{arcsin ( - \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

Simplify

\frac{2 t}{2} = \frac{π}{2} + \frac{arcsin ( - \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{π}{2} + \frac{arcsin ( - \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2} : πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

\frac{π}{2} + \frac{arcsin ( - \frac{y}{3} )}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2}

Group like terms

= \frac{π}{2} + \frac{2 πn}{2} + \frac{\frac{π}{4}}{2} + \frac{arcsin ( - \frac{y}{3} )}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{4}}{2} = \frac{π}{8}

\frac{\frac{π}{4}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{π}{8}

= \frac{π}{2} + πn + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

Group like terms

= πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

t = \frac{arcsin ( \frac{y}{3} )}{2} + πn + \frac{π}{8}, t = πn + \frac{π}{2} + \frac{π}{8} + \frac{arcsin ( - \frac{y}{3} )}{2}

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