What is the general solution for 4cos(2t)=2 ?

The general solution for 4cos(2t)=2 is t= pi/6+pin,t=(5pi)/6+pin

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4cos(2t)=2

Solution

4 cos (2 t) = 2

Solution

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

Degrees

t = 3 0^{\circ} + 18 0^{\circ} n, t = 15 0^{\circ} + 18 0^{\circ} n

Solution steps

4 cos (2 t) = 2

Divide both sides by

4

4 cos (2 t) = 2

Divide both sides by

4

\frac{4 cos ( 2 t )}{4} = \frac{2}{4}

Simplify

cos (2 t) = \frac{1}{2}

cos (2 t) = \frac{1}{2}

General solutions for

cos (2 t) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 t = \frac{π}{3} + 2 πn, 2 t = \frac{5 π}{3} + 2 πn

2 t = \frac{π}{3} + 2 πn, 2 t = \frac{5 π}{3} + 2 πn

Solve

2 t = \frac{π}{3} + 2 πn : t = \frac{π}{6} + πn

2 t = \frac{π}{3} + 2 πn

Divide both sides by

2

2 t = \frac{π}{3} + 2 πn

Divide both sides by

2

\frac{2 t}{2} = \frac{\frac{π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} = \frac{\frac{π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{\frac{π}{3}}{2} + \frac{2 πn}{2} : \frac{π}{6} + πn

\frac{\frac{π}{3}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{3}}{2} = \frac{π}{6}

\frac{\frac{π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{π}{6}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{π}{6} + πn

t = \frac{π}{6} + πn

t = \frac{π}{6} + πn

t = \frac{π}{6} + πn

Solve

2 t = \frac{5 π}{3} + 2 πn : t = \frac{5 π}{6} + πn

2 t = \frac{5 π}{3} + 2 πn

Divide both sides by

2

2 t = \frac{5 π}{3} + 2 πn

Divide both sides by

2

\frac{2 t}{2} = \frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} = \frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2} : \frac{5 π}{6} + πn

\frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

\frac{\frac{5 π}{3}}{2} = \frac{5 π}{6}

\frac{\frac{5 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{5 π}{6}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{5 π}{6} + πn

t = \frac{5 π}{6} + πn

t = \frac{5 π}{6} + πn

t = \frac{5 π}{6} + πn

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

Popular Examples

tan(θ)=(10)/(5.32)

tan (θ) = \frac{10}{5.32}

2cos(x)= 6/7

2 cos (x) = \frac{6}{7}

tan(θ)= 1/2 ,pi<θ<(3pi)/2

tan (θ) = \frac{1}{2}, π < θ < \frac{3 π}{2}

7/2 =3sin(b(pi/2))+2

\frac{7}{2} = 3 sin (b (\frac{π}{2})) + 2

cos(x)= 2/8

cos (x) = \frac{2}{8}

Frequently Asked Questions (FAQ)

What is the general solution for 4cos(2t)=2 ?
The general solution for 4cos(2t)=2 is t= pi/6+pin,t=(5pi)/6+pin