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受欢迎的三角函数 >

(sin(b))/(300)=(sin(49))/(500)

解答

\frac{sin ( b )}{300} = \frac{sin ( 4 9 ^{\circ} )}{500}

解答

b = 0.46993 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.46993 \dots + 36 0^{\circ} n

+1

弧度

b = 0.46993 \dots + 2 πn, b = π - 0.46993 \dots + 2 πn

求解步骤

\frac{sin ( b )}{300} = \frac{sin ( 4 9 ^{\circ} )}{500}

在两边乘以

100

\frac{sin ( b )}{300} = \frac{sin ( 4 9 ^{\circ} )}{500}

在两边乘以

100

\frac{sin ( b )}{300} \cdot 100 = \frac{sin ( 4 9 ^{\circ} )}{500} \cdot 100

化简

\frac{sin ( b )}{300} \cdot 100 = \frac{sin ( 4 9 ^{\circ} )}{500} \cdot 100

化简

\frac{sin ( b )}{300} \cdot 100 : \frac{sin ( b )}{3}

\frac{sin ( b )}{300} \cdot 100

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( b ) \cdot 100}{300}

约分:

100

= \frac{sin ( b )}{3}

化简

\frac{sin ( 4 9 ^{\circ} )}{500} \cdot 100 : \frac{sin ( 4 9 ^{\circ} )}{5}

\frac{sin ( 4 9 ^{\circ} )}{500} \cdot 100

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( 4 9 ^{\circ} ) \cdot 100}{500}

约分:

100

= \frac{sin ( 4 9 ^{\circ} )}{5}

\frac{sin ( b )}{3} = \frac{sin ( 4 9 ^{\circ} )}{5}

\frac{sin ( b )}{3} = \frac{sin ( 4 9 ^{\circ} )}{5}

\frac{sin ( b )}{3} = \frac{sin ( 4 9 ^{\circ} )}{5}

在两边乘以

3

\frac{sin ( b )}{3} = \frac{sin ( 4 9 ^{\circ} )}{5}

在两边乘以

3

\frac{3 sin ( b )}{3} = \frac{3 sin ( 4 9 ^{\circ} )}{5}

化简

sin (b) = \frac{3 sin ( 4 9 ^{\circ} )}{5}

sin (b) = \frac{3 sin ( 4 9 ^{\circ} )}{5}

使用反三角函数性质

sin (b) = \frac{3 sin ( 4 9 ^{\circ} )}{5}

sin (b) = \frac{3 sin ( 4 9 ^{\circ} )}{5}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{3 sin ( 4 9 ^{\circ} )}{5}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{3 sin ( 4 9 ^{\circ} )}{5}) + 36 0^{\circ} n

b = arcsin (\frac{3 sin ( 4 9 ^{\circ} )}{5}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{3 sin ( 4 9 ^{\circ} )}{5}) + 36 0^{\circ} n

以小数形式表示解

b = 0.46993 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.46993 \dots + 36 0^{\circ} n

作图

流行的例子

sin(θ)=cos(2θ+60)

sin (θ) = cos (2 θ + 6 0^{\circ})

tan(θ)=(-12)/5

tan (θ) = \frac{- 12}{5}

(1+tan(x/2))/(1-tan(x/2))=sqrt(4.137131)

\frac{1 + tan ( \frac{x}{2} )}{1 - tan ( \frac{x}{2} )} = 4.137131

cos (θ) = 0.51

csc(θ)=(-2sqrt(3))/3

csc (θ) = \frac{- 2 3}{3}