What is the general solution for cos(t)= 1/3 ,0<t< 1/2 pi ?

The general solution for cos(t)= 1/3 ,0<t< 1/2 pi is t=1.23095…

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cos(t)= 1/3 ,0<t< 1/2 pi

cos (t) = \frac{1}{3}, 0 < t < \frac{1}{2} π

t = 1.23095 \dots

Degrees

t = 70.52877 \dots^{\circ}

Solution steps

cos (t) = \frac{1}{3}, 0 < t < \frac{1}{2} π

Apply trig inverse properties

cos (t) = \frac{1}{3}

General solutions for

cos (t) = \frac{1}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

t = arccos (\frac{1}{3}) + 2 πn, t = 2 π - arccos (\frac{1}{3}) + 2 πn

t = arccos (\frac{1}{3}) + 2 πn, t = 2 π - arccos (\frac{1}{3}) + 2 πn

Solutions for the range

0 < t < \frac{1}{2} π

t = arccos (\frac{1}{3})

Show solutions in decimal form

t = 1.23095 \dots

x, sin (x) - cos (x) = 1

x, sin (x) cos (y) = 1

sin (4 x) cos (7 x) - cos (4 x) sin (7 x) = - 0.6

cos (x) = \frac{40}{41}

sin (x) + cos (x) = 4

What is the general solution for cos(t)= 1/3 ,0<t< 1/2 pi ?
The general solution for cos(t)= 1/3 ,0<t< 1/2 pi is t=1.23095…