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受欢迎的三角函数 >

sqrt(2)sin(x+pi/4)=0

解答

2 sin (x + \frac{π}{4}) = 0

解答

x = 2 πn - \frac{π}{4}, x = π + 2 πn - \frac{π}{4}

+1

度数

x = - 4 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n

求解步骤

2 sin (x + \frac{π}{4}) = 0

两边除以

2

2 sin (x + \frac{π}{4}) = 0

两边除以

2

\frac{2 sin ( x + \frac{π}{4} )}{2} = \frac{0}{2}

化简

sin (x + \frac{π}{4}) = 0

sin (x + \frac{π}{4}) = 0

sin (x + \frac{π}{4}) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x + \frac{π}{4} = 0 + 2 πn, x + \frac{π}{4} = π + 2 πn

x + \frac{π}{4} = 0 + 2 πn, x + \frac{π}{4} = π + 2 πn

解

x + \frac{π}{4} = 0 + 2 πn : x = 2 πn - \frac{π}{4}

x + \frac{π}{4} = 0 + 2 πn

0 + 2 πn = 2 πn

x + \frac{π}{4} = 2 πn

将

\frac{π}{4}

到右边

x + \frac{π}{4} = 2 πn

两边减去

\frac{π}{4}

x + \frac{π}{4} - \frac{π}{4} = 2 πn - \frac{π}{4}

化简

x = 2 πn - \frac{π}{4}

x = 2 πn - \frac{π}{4}

解

x + \frac{π}{4} = π + 2 πn : x = π + 2 πn - \frac{π}{4}

x + \frac{π}{4} = π + 2 πn

将

\frac{π}{4}

到右边

x + \frac{π}{4} = π + 2 πn

两边减去

\frac{π}{4}

x + \frac{π}{4} - \frac{π}{4} = π + 2 πn - \frac{π}{4}

化简

x = π + 2 πn - \frac{π}{4}

x = π + 2 πn - \frac{π}{4}

x = 2 πn - \frac{π}{4}, x = π + 2 πn - \frac{π}{4}

作图

流行的例子

sin(x)=(2(5.5*10^{-7}))/(3.36*10^{-5)}

sin (x) = \frac{2 ( 5.5 \cdot 1 0 ^{- 7} )}{3.36 \cdot 1 0 ^{- 5}}

sin(x-30)=cos(15)

sin (x - 3 0^{\circ}) = cos (1 5^{\circ})

tan (x) = 2.8867

3 = cot (q)

sin(t)+cos(2t)=0

sin (t) + cos (2 t) = 0