What is the general solution for 1=cot(θ) ?

The general solution for 1=cot(θ) is θ= pi/4+pin

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1=cot(θ)

1 = cot (θ)

θ = \frac{π}{4} + πn

Degrees

θ = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

1 = cot (θ)

Switch sides

cot (θ) = 1

General solutions for

cot (θ) = 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

arccos (2 x) = 0

cos (x + 3 0^{\circ}) = 0

cos (2 x) - sin^{2} (x) - \frac{1}{4} = 0

tan (3 x + 1) = 1

- cos (2 x) = 2 cos (2 x) - 1

What is the general solution for 1=cot(θ) ?
The general solution for 1=cot(θ) is θ= pi/4+pin