What is the general solution for tan(β)=2,180<= β<= 270 ?

The general solution for tan(β)=2,180<= β<= 270 is β=1.10714…+180

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tan(β)=2,180<= β<= 270

tan (β) = 2, 18 0^{\circ} \leq β \leq 27 0^{\circ}

β = 1.10714 \dots + 18 0^{\circ}

Radians

β = 1.10714 \dots + π

Solution steps

tan (β) = 2, 18 0^{\circ} \leq β \leq 27 0^{\circ}

Apply trig inverse properties

tan (β) = 2

General solutions for

tan (β) = 2

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

β = arctan (2) + 18 0^{\circ} n

β = arctan (2) + 18 0^{\circ} n

Solutions for the range

18 0^{\circ} \leq β \leq 27 0^{\circ}

β = arctan (2) + 18 0^{\circ}

Show solutions in decimal form

β = 1.10714 \dots + 18 0^{\circ}

cos (x) = \frac{1}{3}, cos (2 x)

3 sin (2 x) \cdot cos (x) = 2 sin^{3} (x)

x, sin (x) \cdot cos (y) = 0

2 cos (3 x - 1) = - 1

\frac{0.866}{sin ( x )} = 1.53

What is the general solution for tan(β)=2,180<= β<= 270 ?
The general solution for tan(β)=2,180<= β<= 270 is β=1.10714…+180