What is the general solution for -5sin(t)=0 ?

The general solution for -5sin(t)=0 is t=2pin,t=pi+2pin

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-5sin(t)=0

- 5 sin (t) = 0

t = 2 πn, t = π + 2 πn

Degrees

t = 0^{\circ} + 36 0^{\circ} n, t = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- 5 sin (t) = 0

Divide both sides by

- 5

- 5 sin (t) = 0

Divide both sides by

- 5

\frac{- 5 sin ( t )}{- 5} = \frac{0}{- 5}

Simplify

sin (t) = 0

sin (t) = 0

General solutions for

sin (t) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = 0 + 2 πn, t = π + 2 πn

t = 0 + 2 πn, t = π + 2 πn

Solve

t = 0 + 2 πn : t = 2 πn

t = 0 + 2 πn

0 + 2 πn = 2 πn

t = 2 πn

t = 2 πn, t = π + 2 πn

4 cos (\frac{θ}{2}) = 3 + 2 cos (θ)

tan (θ + 1 0^{\circ}) = cot (2 θ - 10)

4 sin^{2} (x) = 5 - 2 cos (x)

sin (x + \frac{π}{6}) = - 1

sec (x) = \frac{4}{3}

What is the general solution for -5sin(t)=0 ?
The general solution for -5sin(t)=0 is t=2pin,t=pi+2pin