What is the general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 ?

The general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 is x=-60-360n,x=-120-360n

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sin(60-x)-sin(60+x)=(sqrt(3))/2

Solution

sin (6 0^{\circ} - x) - sin (6 0^{\circ} + x) = \frac{3}{2}

Solution

x = - 6 0^{\circ} - 36 0^{\circ} n, x = - 12 0^{\circ} - 36 0^{\circ} n

Radians

x = - \frac{π}{3} - 2 πn, x = - \frac{2 π}{3} - 2 πn

Solution steps

sin (6 0^{\circ} - x) - sin (6 0^{\circ} + x) = \frac{3}{2}

Rewrite using trig identities

sin (6 0^{\circ} - x) - sin (6 0^{\circ} + x)

Use the Sum to Product identity:

sin (s) - sin (t) = 2 sin (\frac{s - t}{2}) cos (\frac{s + t}{2})

= 2 sin (\frac{6 0 ^{\circ} - x - ( 6 0 ^{\circ} + x )}{2}) cos (\frac{6 0 ^{\circ} - x + 6 0 ^{\circ} + x}{2})

Simplify

2 sin (\frac{6 0 ^{\circ} - x - ( 6 0 ^{\circ} + x )}{2}) cos (\frac{6 0 ^{\circ} - x + 6 0 ^{\circ} + x}{2}) : sin (- x)

2 sin (\frac{6 0 ^{\circ} - x - ( 6 0 ^{\circ} + x )}{2}) cos (\frac{6 0 ^{\circ} - x + 6 0 ^{\circ} + x}{2})

\frac{6 0 ^{\circ} - x - ( 6 0 ^{\circ} + x )}{2} = - x

\frac{6 0 ^{\circ} - x - ( 6 0 ^{\circ} + x )}{2}

Join

6 0^{\circ} - x - (6 0^{\circ} + x) : - 2 x

6 0^{\circ} - x - (6 0^{\circ} + x)

Convert element to fraction:

x = \frac{x 3}{3}, (x + 6 0^{\circ}) = \frac{( 6 0 ^{\circ} + x ) 3}{3}

= 6 0^{\circ} - \frac{x \cdot 3}{3} - \frac{( 6 0 ^{\circ} + x ) \cdot 3}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} - x \cdot 3 - ( 6 0 ^{\circ} + x ) \cdot 3}{3}

Expand

18 0^{\circ} - x \cdot 3 - (6 0^{\circ} + x) \cdot 3 : - 6 x

18 0^{\circ} - x \cdot 3 - (6 0^{\circ} + x) \cdot 3

= 18 0^{\circ} - 3 x - 3 (6 0^{\circ} + x)

Expand

- 3 (6 0^{\circ} + x) : - 18 0^{\circ} - 3 x

- 3 (6 0^{\circ} + x)

Apply the distributive law:

a (b + c) = ab + a c

a = - 3, b = 6 0^{\circ}, c = x

= - 3 \cdot 6 0^{\circ} + (- 3) x

Apply minus-plus rules

+ (- a) = - a

= - 3 \cdot 6 0^{\circ} - 3 x

3 \cdot 6 0^{\circ} = 18 0^{\circ}

3 \cdot 6 0^{\circ}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 18 0^{\circ}

Cancel the common factor:

3

= 18 0^{\circ}

= - 18 0^{\circ} - 3 x

= 18 0^{\circ} - x \cdot 3 - 18 0^{\circ} - 3 x

Simplify

18 0^{\circ} - x \cdot 3 - 18 0^{\circ} - 3 x : - 6 x

18 0^{\circ} - x \cdot 3 - 18 0^{\circ} - 3 x

Group like terms

= - 3 x - 3 x + 18 0^{\circ} - 18 0^{\circ}

Add similar elements:

- 3 x - 3 x = - 6 x

= - 6 x + 18 0^{\circ} - 18 0^{\circ}

Add similar elements:

18 0^{\circ} - 18 0^{\circ} = 0

= - 6 x

= - 6 x

= \frac{- 6 x}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{6 x}{3}

Divide the numbers:

\frac{6}{3} = 2

= - 2 x

= \frac{- 2 x}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= - x

= 2 sin (- x) cos (\frac{x - x + 6 0 ^{\circ} + 6 0 ^{\circ}}{2})

\frac{6 0 ^{\circ} - x + 6 0 ^{\circ} + x}{2} = 6 0^{\circ}

\frac{6 0 ^{\circ} - x + 6 0 ^{\circ} + x}{2}

Combine the fractions

6 0^{\circ} + 6 0^{\circ} : 12 0^{\circ}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} + 18 0 ^{\circ}}{3}

Add similar elements:

18 0^{\circ} + 18 0^{\circ} = 36 0^{\circ}

= 12 0^{\circ}

= \frac{12 0 ^{\circ} - x + x}{2}

Add similar elements:

- x + x = 0

= \frac{12 0 ^{\circ}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{36 0 ^{\circ}}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= 6 0^{\circ}

Cancel the common factor:

2

= 6 0^{\circ}

= 2 cos (6 0^{\circ}) sin (- x)

Simplify

cos (6 0^{\circ}) : \frac{1}{2}

cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= 2 \cdot \frac{1}{2} sin (- x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} sin (- x)

Cancel the common factor:

2

= sin (- x) \cdot 1

Multiply:

sin (- x) \cdot 1 = sin (- x)

= sin (- x)

= sin (- x)

sin (- x) = \frac{3}{2}

General solutions for

sin (- x) = \frac{3}{2}

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

- x = 6 0^{\circ} + 36 0^{\circ} n, - x = 12 0^{\circ} + 36 0^{\circ} n

- x = 6 0^{\circ} + 36 0^{\circ} n, - x = 12 0^{\circ} + 36 0^{\circ} n

Solve

- x = 6 0^{\circ} + 36 0^{\circ} n : x = - 6 0^{\circ} - 36 0^{\circ} n

- x = 6 0^{\circ} + 36 0^{\circ} n

Divide both sides by

- 1

- x = 6 0^{\circ} + 36 0^{\circ} n

Divide both sides by

- 1

\frac{- x}{- 1} = \frac{6 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

Simplify

\frac{- x}{- 1} = \frac{6 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

Simplify

\frac{- x}{- 1} : x

\frac{- x}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

Apply rule

\frac{a}{1} = a

= x

Simplify

\frac{6 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} : - 6 0^{\circ} - 36 0^{\circ} n

\frac{6 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

\frac{6 0 ^{\circ}}{- 1} = - 6 0^{\circ}

\frac{6 0 ^{\circ}}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{6 0 ^{\circ}}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{6 0 ^{\circ}}{1} = 6 0^{\circ}

= - 6 0^{\circ}

= - 6 0^{\circ} + \frac{36 0 ^{\circ} n}{- 1}

\frac{36 0 ^{\circ} n}{- 1} = - 36 0^{\circ} n

\frac{36 0 ^{\circ} n}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} n}{1}

Apply rule

\frac{a}{1} = a

= - 36 0^{\circ} n

= - 6 0^{\circ} - 36 0^{\circ} n

x = - 6 0^{\circ} - 36 0^{\circ} n

x = - 6 0^{\circ} - 36 0^{\circ} n

x = - 6 0^{\circ} - 36 0^{\circ} n

Solve

- x = 12 0^{\circ} + 36 0^{\circ} n : x = - 12 0^{\circ} - 36 0^{\circ} n

- x = 12 0^{\circ} + 36 0^{\circ} n

Divide both sides by

- 1

- x = 12 0^{\circ} + 36 0^{\circ} n

Divide both sides by

- 1

\frac{- x}{- 1} = \frac{12 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

Simplify

\frac{- x}{- 1} = \frac{12 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

Simplify

\frac{- x}{- 1} : x

\frac{- x}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

Apply rule

\frac{a}{1} = a

= x

Simplify

\frac{12 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1} : - 12 0^{\circ} - 36 0^{\circ} n

\frac{12 0 ^{\circ}}{- 1} + \frac{36 0 ^{\circ} n}{- 1}

\frac{12 0 ^{\circ}}{- 1} = - 12 0^{\circ}

\frac{12 0 ^{\circ}}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{12 0 ^{\circ}}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{12 0 ^{\circ}}{1} = 12 0^{\circ}

= - 12 0^{\circ}

= - 12 0^{\circ} + \frac{36 0 ^{\circ} n}{- 1}

\frac{36 0 ^{\circ} n}{- 1} = - 36 0^{\circ} n

\frac{36 0 ^{\circ} n}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} n}{1}

Apply rule

\frac{a}{1} = a

= - 36 0^{\circ} n

= - 12 0^{\circ} - 36 0^{\circ} n

x = - 12 0^{\circ} - 36 0^{\circ} n

x = - 12 0^{\circ} - 36 0^{\circ} n

x = - 12 0^{\circ} - 36 0^{\circ} n

x = - 6 0^{\circ} - 36 0^{\circ} n, x = - 12 0^{\circ} - 36 0^{\circ} n

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Frequently Asked Questions (FAQ)

What is the general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 ?
The general solution for sin(60-x)-sin(60+x)=(sqrt(3))/2 is x=-60-360n,x=-120-360n