What is the general solution for cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x))) ?

The general solution for cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x))) is x= pi/4+pin

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Popular >

cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x)))

Solution

cos (x) - sin (x) = \frac{1}{( sin ( x ) )} - \frac{1}{( cos ( x ) )}

Solution

x = \frac{π}{4} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

cos (x) - sin (x) = \frac{1}{( sin ( x ) )} - \frac{1}{( cos ( x ) )}

Subtract

\frac{1}{sin ( x )} - \frac{1}{cos ( x )}

from both sides

cos (x) - sin (x) - \frac{1}{sin ( x )} + \frac{1}{cos ( x )} = 0

Simplify

cos (x) - sin (x) - \frac{1}{sin ( x )} + \frac{1}{cos ( x )} : \frac{cos ^{2} ( x ) sin ( x ) - sin ^{2} ( x ) cos ( x ) - cos ( x ) + sin ( x )}{sin ( x ) cos ( x )}

cos (x) - sin (x) - \frac{1}{sin ( x )} + \frac{1}{cos ( x )}

Convert element to fraction:

cos (x) = \frac{cos ( x )}{1}, sin (x) = \frac{sin ( x )}{1}

= \frac{cos ( x )}{1} - \frac{sin ( x )}{1} - \frac{1}{sin ( x )} + \frac{1}{cos ( x )}

Least Common Multiplier of

1, 1, sin (x), cos (x) : sin (x) cos (x)

1, 1, sin (x), cos (x)

Lowest Common Multiplier (LCM)

Least Common Multiplier of

1, 1 : 1

1, 1

Least Common Multiplier (LCM)

Prime factorization of

1

Prime factorization of

1

Multiply each factor the greatest number of times it occurs in either

1

1

= 1

Multiply the numbers:

1 = 1

= 1

Compute an expression comprised of factors that appear in at least one of the factored expressions

= sin (x) cos (x)

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

sin (x) cos (x)

For

\frac{cos ( x )}{1} :

multiply the denominator and numerator by

sin (x) cos (x)

\frac{cos ( x )}{1} = \frac{cos ( x ) sin ( x ) cos ( x )}{1 \cdot sin ( x ) cos ( x )} = \frac{cos ^{2} ( x ) sin ( x )}{sin ( x ) cos ( x )}

For

\frac{sin ( x )}{1} :

multiply the denominator and numerator by

sin (x) cos (x)

\frac{sin ( x )}{1} = \frac{sin ( x ) sin ( x ) cos ( x )}{1 \cdot sin ( x ) cos ( x )} = \frac{sin ^{2} ( x ) cos ( x )}{sin ( x ) cos ( x )}

For

\frac{1}{sin ( x )} :

multiply the denominator and numerator by

cos (x)

\frac{1}{sin ( x )} = \frac{1 \cdot cos ( x )}{sin ( x ) cos ( x )} = \frac{cos ( x )}{sin ( x ) cos ( x )}

For

\frac{1}{cos ( x )} :

multiply the denominator and numerator by

sin (x)

\frac{1}{cos ( x )} = \frac{1 \cdot sin ( x )}{cos ( x ) sin ( x )} = \frac{sin ( x )}{sin ( x ) cos ( x )}

= \frac{cos ^{2} ( x ) sin ( x )}{sin ( x ) cos ( x )} - \frac{sin ^{2} ( x ) cos ( x )}{sin ( x ) cos ( x )} - \frac{cos ( x )}{sin ( x ) cos ( x )} + \frac{sin ( x )}{sin ( x ) cos ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ^{2} ( x ) sin ( x ) - sin ^{2} ( x ) cos ( x ) - cos ( x ) + sin ( x )}{sin ( x ) cos ( x )}

\frac{cos ^{2} ( x ) sin ( x ) - sin ^{2} ( x ) cos ( x ) - cos ( x ) + sin ( x )}{sin ( x ) cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos^{2} (x) sin (x) - sin^{2} (x) cos (x) - cos (x) + sin (x) = 0

Factor

cos^{2} (x) sin (x) - sin^{2} (x) cos (x) - cos (x) + sin (x) : (- 1 + cos (x) sin (x)) (cos (x) - sin (x))

cos^{2} (x) sin (x) - sin^{2} (x) cos (x) - cos (x) + sin (x)

Factor

cos^{2} (x) sin (x) - cos (x) : cos (x) (cos (x) sin (x) - 1)

cos^{2} (x) sin (x) - cos (x)

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

cos^{2} (x) = cos (x) cos (x)

= cos (x) cos (x) sin (x) - cos (x)

Factor out common term

cos (x)

= cos (x) (cos (x) sin (x) - 1)

Factor

- sin^{2} (x) cos (x) + sin (x) : sin (x) (- sin (x) cos (x) + 1)

- sin^{2} (x) cos (x) + sin (x)

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

sin^{2} (x) = sin (x) sin (x)

= - sin (x) sin (x) cos (x) + sin (x)

Factor out common term

sin (x)

= sin (x) (- sin (x) cos (x) + 1)

= cos (x) (cos (x) sin (x) - 1) + sin (x) (- sin (x) cos (x) + 1)

Rewrite as

= (- 1 + cos (x) sin (x)) cos (x) - (- 1 + cos (x) sin (x)) sin (x)

Factor out common term

(- 1 + cos (x) sin (x))

= (- 1 + cos (x) sin (x)) (cos (x) - sin (x))

(- 1 + cos (x) sin (x)) (cos (x) - sin (x)) = 0

Solving each part separately

- 1 + cos (x) sin (x) = 0 or cos (x) - sin (x) = 0

- 1 + cos (x) sin (x) = 0 :

No Solution

- 1 + cos (x) sin (x) = 0

Rewrite using trig identities

- 1 + cos (x) sin (x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= - 1 + \frac{sin ( 2 x )}{2}

- 1 + \frac{sin ( 2 x )}{2} = 0

Move

1

to the right side

- 1 + \frac{sin ( 2 x )}{2} = 0

Add

1

to both sides

- 1 + \frac{sin ( 2 x )}{2} + 1 = 0 + 1

Simplify

\frac{sin ( 2 x )}{2} = 1

\frac{sin ( 2 x )}{2} = 1

Multiply both sides by

2

\frac{sin ( 2 x )}{2} = 1

Multiply both sides by

2

\frac{2 sin ( 2 x )}{2} = 1 \cdot 2

Simplify

sin (2 x) = 2

sin (2 x) = 2

- 1 \leq sin (x) \leq 1

No Solution

cos (x) - sin (x) = 0 : x = \frac{π}{4} + πn

cos (x) - sin (x) = 0

Rewrite using trig identities

cos (x) - sin (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{cos ( x ) - sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

1 - \frac{sin ( x )}{cos ( x )} = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 - tan (x) = 0

1 - tan (x) = 0

Move

1

to the right side

1 - tan (x) = 0

Subtract

1

from both sides

1 - tan (x) - 1 = 0 - 1

Simplify

- tan (x) = - 1

- tan (x) = - 1

Divide both sides by

- 1

- tan (x) = - 1

Divide both sides by

- 1

\frac{- tan ( x )}{- 1} = \frac{- 1}{- 1}

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

Popular Examples

sin^2(x)+cos^5(x)=2

sin^{2} (x) + cos^{5} (x) = 2

16=4+9-12cos(x)

16 = 4 + 9 - 12 cos (x)

tanh(z)+2=0

tanh (z) + 2 = 0

cos^2(a)= 2/(3sin(a))

cos^{2} (a) = \frac{2}{3 sin ( a )}

5cos(5x)=2

5 cos (5 x) = 2

Frequently Asked Questions (FAQ)

What is the general solution for cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x))) ?
The general solution for cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x))) is x= pi/4+pin