What is the general solution for sin^{22}(x)sin^3(x)+6=18 ?

The general solution for sin^{22}(x)sin^3(x)+6=18 is No Solution for x\in\mathbb{R}

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sin^{22}(x)sin^3(x)+6=18

sin^{22} (x) sin^{3} (x) + 6 = 18

No Solution for x \in R

Solution steps

sin^{22} (x) sin^{3} (x) + 6 = 18

Simplify

sin^{22} (x) sin^{3} (x) + 6 : sin^{25} (x) + 6

sin^{22} (x) sin^{3} (x) + 6

sin^{22} (x) sin^{3} (x) = sin^{25} (x)

sin^{22} (x) sin^{3} (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

sin^{22} (x) sin^{3} (x) = sin^{22 + 3} (x)

= sin^{22 + 3} (x)

Add the numbers:

22 + 3 = 25

= sin^{25} (x)

= sin^{25} (x) + 6

sin^{25} (x) + 6 = 18

Move

6

to the right side

sin^{25} (x) + 6 = 18

Subtract

6

from both sides

sin^{25} (x) + 6 - 6 = 18 - 6

Simplify

sin^{25} (x) = 12

sin^{25} (x) = 12

For

x^{n} = f (a)

, n is odd, the solution is

- 1 \leq sin (x) \leq 1

No Solution for x \in R

d^{2} + 4 d + 4 = sin (x)

8 cos (a) - 15 sin (a) = 0

tan (t) = \frac{3}{tan ( t )}

tan (- x) = tan (2 x + 1)

(2 cos (x) - sin (x)) (1 + sin (x)) = cos^{2} (x)

What is the general solution for sin^{22}(x)sin^3(x)+6=18 ?
The general solution for sin^{22}(x)sin^3(x)+6=18 is No Solution for x\in\mathbb{R}