What is the general solution for -4cos^2(x)=0 ?

The general solution for -4cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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-4cos^2(x)=0

- 4 cos^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

- 4 cos^{2} (x) = 0

Divide both sides by

- 4

- 4 cos^{2} (x) = 0

Divide both sides by

- 4

- 4 cos^{2} (x) = 0

Divide both sides by

- 4

\frac{- 4 cos ^{2} ( x )}{- 4} = \frac{0}{- 4}

Simplify

cos^{2} (x) = 0

cos^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sin^{2} (x) - 4 sin^{2} (x) + 7 cos^{2} (x) = 0

(sin (x)) (cos (x)) = 0

sin^{2} (x) - 15 sin (x) cos (x) + 50 cos^{2} (x) = 0

cot (x) = sin^{2} (x)

sec (2 x + 60) = - 1.5

What is the general solution for -4cos^2(x)=0 ?
The general solution for -4cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin