en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^5(x)+sin(x)+2sin^2(x)=1

Solution

sin^{5} (x) + sin (x) + 2 sin^{2} (x) = 1

Solution

x = 0.51263 \dots + 2 πn, x = π - 0.51263 \dots + 2 πn

+1

Solution steps

sin^{5} (x) + sin (x) + 2 sin^{2} (x) = 1

Solve by substitution

sin (x) \approx 0.49047 \dots

sin (x) = 0.49047 \dots : x = arcsin (0.49047 \dots) + 2 πn, x = π - arcsin (0.49047 \dots) + 2 πn

Combine all the solutions

x = arcsin (0.49047 \dots) + 2 πn, x = π - arcsin (0.49047 \dots) + 2 πn

Show solutions in decimal form

x = 0.51263 \dots + 2 πn, x = π - 0.51263 \dots + 2 πn

Popular Examples

(2cos(x)-1)*(2sin(x)+1)=3-4sin^2(x)

(2 cos (x) - 1) \cdot (2 sin (x) + 1) = 3 - 4 sin^{2} (x)

r=(2a)/((1+cos(x)))

r = \frac{2 a}{( 1 + cos ( x ) )}

cos^3(x)+cos^2(x)+cos(x)+1=0

cos^{3} (x) + cos^{2} (x) + cos (x) + 1 = 0

(cos^4(x))/3 =sin^2(x)

\frac{cos ^{4} ( x )}{3} = sin^{2} (x)

sin^3(x)cos(x)-sin^2(x)=0

sin^{3} (x) cos (x) - sin^{2} (x) = 0

Frequently Asked Questions (FAQ)

What is the general solution for sin^5(x)+sin(x)+2sin^2(x)=1 ?
The general solution for sin^5(x)+sin(x)+2sin^2(x)=1 is x=0.51263…+2pin,x=pi-0.51263…+2pin