What is the general solution for sin(x)cos(x-60)=0 ?

The general solution for sin(x)cos(x-60)=0 is x=360n,x=180+360n,x=360n+150,x=360n+330

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sin(x)cos(x-60)=0

sin (x) cos (x - 6 0^{\circ}) = 0

x = 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} n + 15 0^{\circ}, x = 36 0^{\circ} n + 33 0^{\circ}

Solution steps

sin (x) cos (x - 6 0^{\circ}) = 0

Solving each part separately

sin (x) = 0 or cos (x - 6 0^{\circ}) = 0

sin (x) = 0 : x = 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

cos (x - 6 0^{\circ}) = 0 : x = 36 0^{\circ} n + 15 0^{\circ}, x = 36 0^{\circ} n + 33 0^{\circ}

Combine all the solutions

x = 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} n + 15 0^{\circ}, x = 36 0^{\circ} n + 33 0^{\circ}

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cos (x) + cos^{4} (x) = \frac{1}{2}

sin^{2} (x) = sec (x)

5 sin^{2} (x) - 11 sin (x) + 2 = 0

3 cos^{2} (x) - sin^{2} (x) - sin^{2} (x) = 0

What is the general solution for sin(x)cos(x-60)=0 ?
The general solution for sin(x)cos(x-60)=0 is x=360n,x=180+360n,x=360n+150,x=360n+330