What is the general solution for solvefor y,y=sin(3t)u(t)*u(t) ?

The general solution for solvefor y,y=sin(3t)u(t)*u(t) is y=t^2u^2sin(3t)

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solvefor y,y=sin(3t)u(t)*u(t)

solve for

y, y = sin (3 t) u (t) \cdot u (t)

y = t^{2} u^{2} sin (3 t)

Solution steps

y = sin (3 t) u (t) u (t)

Simplify

sin (3 t) u (t) u (t) : t^{2} u^{2} sin (3 t)

sin (3 t) u (t) u (t)

Remove parentheses:

(a) = a

= sin (3 t) u t u t

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tt = t^{1 + 1}

= sin (3 t) uu t^{1 + 1}

Add the numbers:

1 + 1 = 2

= sin (3 t) uu t^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= sin (3 t) u^{1 + 1} t^{2}

Add the numbers:

1 + 1 = 2

= sin (3 t) u^{2} t^{2}

y = t^{2} u^{2} sin (3 t)

t, cot (a \cdot) (1 - sec (2 a)) + tan^{2} (a) = 1

y = 7 cos^{2} (- 3)

cos (22 0^{\circ}) = \frac{a}{3}

c, 1 f = 3 cos (x) - 4 sec (x) + 3

y = cos^{215} (0) - sin^{215} (0)

What is the general solution for solvefor y,y=sin(3t)u(t)*u(t) ?
The general solution for solvefor y,y=sin(3t)u(t)*u(t) is y=t^2u^2sin(3t)