What is the general solution for solvefor t,1+tan(a/1)-tan(a)=tan(45+a) ?

The general solution for solvefor t,1+tan(a/1)-tan(a)=tan(45+a) is True for all t;\quad 1=tan(45+a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor t,1+tan(a/1)-tan(a)=tan(45+a)

solve for

t, 1 + tan (\frac{a}{1}) - tan (a) = tan (4 5^{\circ} + a)

True for all t; 1 = tan (4 5^{\circ} + a)

Solution steps

1 + tan (\frac{a}{1}) - tan (a) = tan (4 5^{\circ} + a)

Simplify

1 + tan (\frac{a}{1}) - tan (a) : 1

1 + tan (\frac{a}{1}) - tan (a)

Apply rule

\frac{a}{1} = a

= 1 + tan (a) - tan (a)

Add similar elements:

tan (a) - tan (a) = 0

= 1

1 = tan (4 5^{\circ} + a)

Both sides are equal

True for all t; 1 = tan (4 5^{\circ} + a)

x = a sin (0)

c, d^{4} + 1 = cosh (x) + sinh^{3} (x)

c, cos (3 x) - cos (x) = sin (3 x) - sin (x)

2 x = sin (9 0^{\circ})

c, 10 cos (x) - 24 sin (2 x) = 13

What is the general solution for solvefor t,1+tan(a/1)-tan(a)=tan(45+a) ?
The general solution for solvefor t,1+tan(a/1)-tan(a)=tan(45+a) is True for all t;\quad 1=tan(45+a)