ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

solvefor y,d^2-4d+4y=e^2x+x^2+x+sin^2(x)

解

解く

y, d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

解

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

解答ステップ

d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

d^{2}

を右側に移動します

d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

両辺から

d^{2}

を引く

d^{2} - 4 d + 4 y - d^{2} = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

簡素化

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

4 d

を右側に移動します

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

両辺に

4 d

を足す

- 4 d + 4 y + 4 d = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

簡素化

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

以下で両辺を割る

4

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

以下で両辺を割る

4

\frac{4 y}{4} = \frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

簡素化

\frac{4 y}{4} = \frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

簡素化

\frac{4 y}{4} : y

\frac{4 y}{4}

数を割る:

\frac{4}{4} = 1

= y

簡素化

\frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4} : \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

\frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

グラフ

人気の例

solvefor y,(d^2-5d+6)*y=x+sin^3(x)

so l v e f or y, (d^{2} - 5 d + 6) \cdot y = x + sin^{3} (x)

solvefor t,cot(x)sin^2(x)=1+cos^2(x)

so l v e f or t, cot (x) sin^{2} (x) = 1 + cos^{2} (x)

solvefor f,(6)f=t^{sin(t)}

so l v e f or f, (6) f = t^{s i n (t)}

solvefor c,5cos(2x)+sin(x)+cos(x)+6=0

so l v e f or c, 5 cos (2 x) + sin (x) + cos (x) + 6 = 0

solvefor y,7y=sin^2(x)-4sin(x)+3

so l v e f or y, 7 y = sin^{2} (x) - 4 sin (x) + 3