What is the general solution for cos(θ)= 4/5 ,270<θ<360 ?

The general solution for cos(θ)= 4/5 ,270<θ<360 is θ=360-0.64350…

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Find the Trig Value cos(theta)=4/5 , 270 degrees <theta<360 degrees

cos (θ) = \frac{4}{5}, 27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - 0.64350 \dots

Radians

θ = 2 π - 0.64350 \dots

Solution steps

cos (θ) = \frac{4}{5}, 27 0^{\circ} < θ < 36 0^{\circ}

Apply trig inverse properties

cos (θ) = \frac{4}{5}

General solutions for

cos (θ) = \frac{4}{5}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{4}{5}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{4}{5}) + 36 0^{\circ} n

θ = arccos (\frac{4}{5}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{4}{5}) + 36 0^{\circ} n

Solutions for the range

27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - arccos (\frac{4}{5})

Show solutions in decimal form

θ = 36 0^{\circ} - 0.64350 \dots

tan (\frac{( 5 π )}{6})

sin (\frac{200}{90})

x, tan (x) = 2

x, cos (2 x) = - cos (x)

sin (\frac{( 2 π )}{3})

What is the general solution for cos(θ)= 4/5 ,270<θ<360 ?
The general solution for cos(θ)= 4/5 ,270<θ<360 is θ=360-0.64350…