What is the value of cos(pi/2+pi) ?

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cos(pi/2+pi)

cos (\frac{π}{2} + π)

0

Solution steps

cos (\frac{π}{2} + π)

Rewrite using trig identities:

cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

= cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

Use the following trivial identity:

cos (π) = (- 1)

Use the following trivial identity:

cos (\frac{π}{2}) = 0

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

sin (\frac{π}{2}) = 1

= (- 1) \cdot 0 - 0 \cdot 1

Simplify

= 0

cos (arccos (- \frac{10}{13}))

arcsin (\frac{1}{10})

sin (π) - sin (- π)

cos (4 0^{\circ}) cos (2 0^{\circ}) - sin (4 0^{\circ}) sin (2 0^{\circ})

cos (3 \frac{π}{4})